4ln((x/4)^2-1)

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Solution for 4ln((x/4)^2-1) equation:


D( x )

(x/4)^2-1 <= 0

(x/4)^2-1 <= 0

(x/4)^2-1 <= 0

1/16*x^2 <= 1

1/16*x^2 <= 1 // : 1/16

x^2 <= 1/1/16

x^2 <= 16

x^2 <= 16 // ^ 1/2

abs(x) <= 4

x in <-4:4>

x in (-oo:-4) U (4:+oo)

4*ln((x/4)^2-1) = 0

4*ln((x/4)^2-1) = 0 // : 4

ln((x/4)^2-1) = 0

ln((x/4)^2-1) = ln(e^0)

(x/4)^2-1 = e^0

(x/4)^2-e^0-1 = 0

1/16*x^2 = 2 // : 1/16

x^2 = 32

x^2 = 32 // ^ 1/2

abs(x) = 4*2^(1/2)

x = 4*2^(1/2) or x = -(4*2^(1/2))

x in { 4*2^(1/2), -(4*2^(1/2)) }

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